raw.append returning NoneType?

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1

?Hello,

    I am trying to append two raw files and then write their combination into a third file as follows (see https://mail.nmr.mgh.harvard.edu/pipermail//mne_analysis/2013-July/001569.html ):

import mne

raw1 = mne.io.raw(raw_file_name_1)

raw2 = mne.io.raw(raw_file_name_2)

raw = raw1.append(raw2)

raw.save(combined_file_name)

But receive the following error at the 'save' step: AttributeError: 'NoneType' object has no attribute 'save'

This feels like something obvious, but I can't seem to find it. I am running the python code from the development tree, downloaded about a month ago. I think the relevant file is io/base.py, which is as follows:

-rw-rw-r-- 1 lysne lysne 75207 Oct 11 13:35 base.py

Thanks for everyone's help,

Per Lysne

University of New Mexico
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2

Hi Per,

`.append` follows the semantics of Python lists in operating in place.
Invoking .append on a Raw object just appends the data:

raw1.append(raw2)

Then move on with raw1 which now also incluedes the data from raw2.

HTH,
Denis

2014-11-09 22:22 GMT+01:00 Per Arnold Lysne <lysne at unm.edu>:

?Hello,

     I am trying to append two raw files and then write their combination
into a third file as follows (see
[Mne_analysis] Concatenating raw instances with Raw.append
):

import mne

raw1 = mne.io.raw(raw_file_name_1)

raw2 = mne.io.raw(raw_file_name_2)

raw = raw1.append(raw2)

raw.save(combined_file_name)

But receive the following error at the 'save' step: AttributeError:
'NoneType' object has no attribute 'save'

This feels like something obvious, but I can't seem to find it. I am
running the python code from the development tree, downloaded about a month
ago. I think the relevant file is io/base.py, which is as follows:

-rw-rw-r-- 1 lysne lysne 75207 Oct 11 13:35 base.py

Thanks for everyone's help,

Per Lysne

University of New Mexico

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